.25r^2=49

Solution for .25r^2=49 equation:

.25r^2=49

We move all terms to the left:

.25r^2-(49)=0

a = .25; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·.25·(-49)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-7}{2*.25}=\frac{-7}{0.5}
=-14
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+7}{2*.25}=\frac{7}{0.5}
=14
$